Difference between revisions of "1997 AJHSME Problems/Problem 1"

Revision as of 23:26, 4 July 2013

$\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000} =$

$\text{(A)}\ 0.0026 \qquad \text{(B)}\ 0.0197 \qquad \text{(C)}\ 0.1997 \qquad \text{(D)}\ 0.26 \qquad \text{(E)}\ 1.997$

Convert each fraction to a decimal.

$\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000}$

$0.1+0.09+0.009+0.0007=0.1997$

$\boxed{\textbf{(C)}}$

1997 AJHSME (Problems • Answer Key • Resources)
Preceded by First question	Followed by Problem 2
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All AJHSME/AMC 8 Problems and Solutions

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 * [[AJHSME Problems and Solutions]]
 * [[Mathematics competition resources]]
+{{MAA Notice}}