Difference between revisions of "2012 AMC 10B Problems/Problem 16"

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Three circles with radius 2 are mutually tangent. What is the total area of the circles and the region bounded by them?

$\text{(A)}\ 10\pi+4\sqrt{3}\qquad\text{(B)}\ 13\pi-\sqrt{3}\qquad\text{(C)}\ 12\pi+\sqrt{3}\qquad\text{(D)}\ 10\pi+9\qquad\text{(E)}\ 13\pi$

To determine the area of the figure, you can connect the centers of the circles to form an equilateral triangle of length $4$ . Find the area of this triangle to include the figure formed in between the circles. This area is $4\sqrt{3}$ .

To find the area of the remaining sectors, notice that the sectors have a central angle of 300 because 60 degrees were "used up" for the triangle. The area of one sector is $2^2 \pi * 5/6 = 10\pi/3$ . Then this area is multiplied by three to find the total area of the sectors $(10 \pi)$ . This result is added to area of the equilateral triangle to get a final answer of $10\pi + 4\sqrt3$ .

This means $(A)$ is the right answer. The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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	This means <math>(A)</math> is the right answer.		This means <math>(A)</math> is the right answer.
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Difference between revisions of "2012 AMC 10B Problems/Problem 16"

Revision as of 12:16, 4 July 2013