Difference between revisions of "2013 AMC 12B Problems/Problem 3"
(→See also) |
(→See also) |
||
| Line 12: | Line 12: | ||
{{AMC12 box|year=2013|ab=B|num-b=2|num-a=4}} | {{AMC12 box|year=2013|ab=B|num-b=2|num-a=4}} | ||
{{AMC10 box|year=2013|ab=B|num-b=3|num-a=5}} | {{AMC10 box|year=2013|ab=B|num-b=3|num-a=5}} | ||
| + | {{MAA Notice}} | ||
Revision as of 13:01, 3 July 2013
- The following problem is from both the 2013 AMC 12B #3 and 2013 AMC 10B #4, so both problems redirect to this page.
Problem
When counting from 
to 
, 
is the 
number counted. When counting backwards from to , is the 
number counted. What is 
?
Solution
Note that is equal to the number of integers between and , inclusive. Thus, 
See also
| 2013 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2013 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
