Difference between revisions of "2005 AMC 10A Problems/Problem 18"
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==Solution== | ==Solution== | ||
| − | There are | + | There are at most <math>5</math> games played. |
If team B won the first two games, team A would need to win the next three games. So the only possible order of wins is BBAAA. | If team B won the first two games, team A would need to win the next three games. So the only possible order of wins is BBAAA. | ||
Revision as of 21:40, 21 May 2013
Problem
Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game, there are no ties, and the outcomes of the individual games are independent. If team B wins the second game and team A wins the series, what is the probability that team B wins the first game?
Solution
There are at most 
games played.
If team B won the first two games, team A would need to win the next three games. So the only possible order of wins is BBAAA.
If team A won the first game, and team B won the second game, the possible order of wins are: ABBAA, ABABA, and ABAAX, where X denotes that the 5th game wasn't played.
Since ABAAX is dependent on the outcome of 
games instead of , it is twice as likely to occur and can be treated as two possibilities.
Since there is 
possibility where team B wins the first game and total possibilities, the desired probability is 
