Difference between revisions of "2013 AMC 12A Problems/Problem 3"
(Created page with "We are given that 6/10, or 3/5 of the flowers are pink, so we know 2/5 of the flowers are red. Since 1/3 of the pink flowers are roses, 2/3 of the pink flowers are carnations. ...") |
Epicwisdom (talk | contribs) (LaTeX formatting) |
||
| Line 1: | Line 1: | ||
| − | We are given that 6 | + | We are given that <math>\frac{6}{10} = \frac{3}{5}</math> of the flowers are pink, so we know <math>\frac{2}{5}</math> of the flowers are red. |
| − | Since 1/ | + | Since <math>\frac{1}{3}</math> of the pink flowers are roses, <math>\frac{2}{3}</math> of the pink flowers are carnations. |
| − | We are given that 3/ | + | We are given that <math>\frac{3}{4}</math> of the red flowers are carnations. |
The number of carnations are | The number of carnations are | ||
| − | + | <math>\frac{3}{5} * \frac{2}{3} + \frac{2}{5} * \frac{3}{4} = \frac{2}{5} + \frac{3}{10} = \frac{7}{10} = 10\%</math> | |
Revision as of 03:24, 7 February 2013
We are given that 
of the flowers are pink, so we know 
of the flowers are red.
Since 
of the pink flowers are roses, 
of the pink flowers are carnations.
We are given that 
of the red flowers are carnations.
The number of carnations are
