Difference between revisions of "2011 AMC 10A Problems/Problem 1"
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</math> \textbf{(A)}\ <math> </math>24.00 \qquad\textbf{(B)}\ <math> </math>24.50 \qquad\textbf{(C)}\ <math> </math>25.50\qquad\textbf{(D)}\ <math> </math>28.00\qquad\textbf{(E)}\ <math> </math>30.00 <math> | </math> \textbf{(A)}\ <math> </math>24.00 \qquad\textbf{(B)}\ <math> </math>24.50 \qquad\textbf{(C)}\ <math> </math>25.50\qquad\textbf{(D)}\ <math> </math>28.00\qquad\textbf{(E)}\ <math> </math>30.00 <math> | ||
| − | + | == Solution == | |
</math>30.5-30 = .5<math> hours which is </math>30<math> minutes. </math>30*10=300<math> cents which is </math>3<math> dollars. </math>100*.05=5<math> dollars. So finally </math>20+3+5=28<math> dollars. </math>\longrightarrow \boxed{\textbf{D}}$ | </math>30.5-30 = .5<math> hours which is </math>30<math> minutes. </math>30*10=300<math> cents which is </math>3<math> dollars. </math>100*.05=5<math> dollars. So finally </math>20+3+5=28<math> dollars. </math>\longrightarrow \boxed{\textbf{D}}$ | ||
== See Also == | == See Also == | ||
{{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}} | {{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}} | ||
Revision as of 17:54, 3 February 2013
Problem 1
A cell phone plan costs 
20
5
10
30
100
30.5
\textbf{(A)}\ $$ (Error compiling LaTeX. Unknown error_msg)24.00 \qquad\textbf{(B)}\ $$ (Error compiling LaTeX. Unknown error_msg)24.50 \qquad\textbf{(C)}\ $$ (Error compiling LaTeX. Unknown error_msg)25.50\qquad\textbf{(D)}\ $$ (Error compiling LaTeX. Unknown error_msg)28.00\qquad\textbf{(E)}\ $$ (Error compiling LaTeX. Unknown error_msg)30.00 
30.5-30 = .5
30
30*10=300
3
100*.05=5
20+3+5=28\longrightarrow \boxed{\textbf{D}}$
See Also
| 2011 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
