Difference between revisions of "1993 AJHSME Problems/Problem 16"
Mrdavid445 (talk | contribs) (Created page with "==Problem== <math> \frac{1}{1+\frac{1}{2+\frac{1}{3}}}= </math> <math> \text{(A)}\ 81.0\qquad\text{(B)}\ 82.7\qquad\text{(C)}\ 83.0\qquad\text{(D)}\ 84.0\qquad\text{(E)}\ 84.3 ...") |
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<math> \frac{1}{1+\frac{1}{2+\frac{1}{3}}}= </math> | <math> \frac{1}{1+\frac{1}{2+\frac{1}{3}}}= </math> | ||
| − | <math> \text{(A)}\ | + | <math>\text{(A)}\ \dfrac{1}{6} \qquad \text{(B)}\ \dfrac{3}{10} \qquad \text{(C)}\ \dfrac{7}{10} \qquad \text{(D)}\ \dfrac{5}{6} \qquad \text{(E)}\ \dfrac{10}{3}</math> 84.3 $ |
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| + | ==Solution== | ||
| + | <cmath>\frac{1}{1+\frac{1}{2+\frac13}} = \frac{1}{1+\frac{1}{\frac73}} = \frac{1}{1+\frac37} = \frac{1}{\frac{10}{7}} = \boxed{\text{(C)}\ \frac{7}{10}} </cmath> | ||
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| + | ==See Also== | ||
| + | {{AJHSME box|year=1993|num-b=15|num-a=17}} | ||
84.3 $
![\[\frac{1}{1+\frac{1}{2+\frac13}} = \frac{1}{1+\frac{1}{\frac73}} = \frac{1}{1+\frac37} = \frac{1}{\frac{10}{7}} = \boxed{\text{(C)}\ \frac{7}{10}}\]](http://latex.artofproblemsolving.com/2/0/4/2049d00fe79ffb05b164c4a606d39f0b6e11449b.png)
