Difference between revisions of "2010 AMC 8 Problems/Problem 6"

(Solution)
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Therefore, the answer is <math> \textbf{(E)}\ \text{square} </math>.
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Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2010|num-b=5|num-a=7}}
 
{{AMC8 box|year=2010|num-b=5|num-a=7}}

Revision as of 18:08, 4 November 2012

Problem

Which of the following has the greatest number of line of symmetry? $\textbf{(A)}\ \text{ Equilateral Triangle}$ $\textbf{(B)}\ \text{Non-square rhombus}$ $\textbf{(C)}\ \text{Non-square rectangle}$ $\textbf{(D)}\ \text{Isosceles Triangle}$ $\textbf{(E)}\ \text{Square}$

Solution

An equilateral triangle has 3 lines of symmetry. A non-square rhombus has 2 lines of symmetry. A non-square rectangle has 2 lines of symmetry. An isosceles trapezoid has 1 line of symmetry. A square has 8 lines of symmetry.


Therefore, the answer is $\boxed{ \textbf{(E)}\ \text{square} }$.

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions