Difference between revisions of "2010 AMC 8 Problems/Problem 6"

(See Also)
Line 9: Line 9:
  
 
==See Also==
 
==See Also==
{{AMC8 box|year=2010|num-b=4|num-a=6}}
+
{{AMC8 box|year=2010|num-b=5|num-a=7}}

Revision as of 17:53, 4 November 2012

An equilateral triangle has 3 lines of symmetry. A non-square rhombus has 2 lines of symmetry. A non-square rectangle has 2 lines of symmetry. An isosceles trapezoid has 1 line of symmetry. A square has 8 lines of symmetry.


Therefore, the answer is $\textbf{(E)}\ \text{square}$.

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions