Difference between revisions of "2010 AMC 8 Problems/Problem 6"
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Therefore, the answer is <math> \textbf{(E)}\ \text{square} </math>. | Therefore, the answer is <math> \textbf{(E)}\ \text{square} </math>. | ||
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| + | ==See Also== | ||
| + | {{AMC8 box|year=2010|num-b=4|num-a=6}} | ||
Revision as of 23:24, 3 November 2012
An equilateral triangle has 3 lines of symmetry. A non-square rhombus has 2 lines of symmetry. A non-square rectangle has 2 lines of symmetry. An isosceles trapezoid has 1 line of symmetry. A square has 8 lines of symmetry.
Therefore, the answer is 
.
See Also
| 2010 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
