Difference between revisions of "2005 IMO Shortlist Problems/N2"
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It is clear that <math>a_i=a_j</math> if and only if <math>i=j</math>, or the sequence would not satisfy the specified property. | It is clear that <math>a_i=a_j</math> if and only if <math>i=j</math>, or the sequence would not satisfy the specified property. | ||
− | If <math>|a_i-a_j|\geq \max(i,j)</math>, then <math>a_i</math> and <math>a_j</math> leave the same remainder when divided by <math> | + | If <math>|a_i-a_j|\geq \max(i,j)</math>, then <math>a_i</math> and <math>a_j</math> leave the same remainder when divided by <math>|a_i-a_j|</math>, which violates the given condition for the sequence. It then follows that <math>|a_i-a_j|<\max(i,j)</math> for all positive integers <math>i</math> and <math>j</math>. Now consider <math>\min(a_1,a_2,\ldots,a_n)</math>, and let this be <math>a_k</math>, with <math>k\in [1,n]</math>. It follows that <math>a_1,a_2,\ldots a_{n}</math> are all in the closed interval <math>[a_k,a_k+n-1]</math>, and hence <math>a_1,a_2,\ldots a_n</math> is a permutation of <math>n</math> consecutive numbers, for all <math>n</math>. |
− | Note that there are infinitely many positive and negative terms. Therefore for any arbitrarily large integer <math>\Delta</math> there exists an <math>i</math> such that <math>a_i\geq \Delta</math> and a <math>j</math> such that <math>a_j\leq -\Delta</math>. Since <math>a_1,a_2,\ldots, a_n</math> is a permutation of <math>n</math> consecutive integers, it follows that every integer in the range <math>[-\Delta,\Delta]</math> is in the sequence, and consequently every integer occurs in the sequence. | + | Note that there are infinitely many positive and negative terms. Therefore for any arbitrarily large integer <math>\Delta</math> there exists an <math>i</math> such that <math>a_i\geq \Delta</math> and a <math>j</math> such that <math>a_j\leq -\Delta</math>. Since <math>a_1,a_2,\ldots, a_n</math> is a permutation of <math>n</math> consecutive integers, it follows that every integer in the range <math>[-\Delta,\Delta]</math> is in the sequence, and consequently every integer occurs in the sequence. |
== See Also == | == See Also == |
Revision as of 09:43, 1 September 2012
Problem
Let be a sequence of integers with infinitely many positive and negative terms. Suppose that for every positive integer the numbers leave different remainders upon division by .
Prove that every integer occurs exactly once in the sequence .
Solution
It is clear that if and only if , or the sequence would not satisfy the specified property.
If , then and leave the same remainder when divided by , which violates the given condition for the sequence. It then follows that for all positive integers and . Now consider , and let this be , with . It follows that are all in the closed interval , and hence is a permutation of consecutive numbers, for all .
Note that there are infinitely many positive and negative terms. Therefore for any arbitrarily large integer there exists an such that and a such that . Since is a permutation of consecutive integers, it follows that every integer in the range is in the sequence, and consequently every integer occurs in the sequence.