Difference between revisions of "1950 AHSME Problems/Problem 32"

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\textbf{(D)}\ 8\text{ ft} \qquad
 
\textbf{(D)}\ 8\text{ ft} \qquad
 
\textbf{(E)}\ 4\text{ ft}</math>
 
\textbf{(E)}\ 4\text{ ft}</math>
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==Solution==
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{{solution}}
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==See Also==
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{{AHSME 50p box|year=1950|num-b=31|num-a=33}}
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[[Category:Introductory Geometry Problems]]

Revision as of 07:35, 29 April 2012

Problem

A $25$ foot ladder is placed against a vertical wall of a building. The foot of the ladder is $7$ feet from the base of the building. If the top of the ladder slips $4$ feet, then the foot of the ladder will slide:

$\textbf{(A)}\ 9\text{ ft} \qquad \textbf{(B)}\ 15\text{ ft} \qquad \textbf{(C)}\ 5\text{ ft} \qquad \textbf{(D)}\ 8\text{ ft} \qquad \textbf{(E)}\ 4\text{ ft}$

Solution

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See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 31
Followed by
Problem 33
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All AHSME Problems and Solutions