Difference between revisions of "2012 AMC 12B Problems/Problem 1"

Line 7: Line 7:
 
== Solution ==
 
== Solution ==
 
Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get  
 
Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get  
64 which is choice '''C'''
+
<math>\boxed{\textbf{(E)}\ 64}</math>

Revision as of 18:47, 23 February 2012

Problem

Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?

$\textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80$

Solution

Multiplying 18 and 2 by 4 we get 72 and 8 students and rabbits respectively. Subtracting 72 from 8 we get $\boxed{\textbf{(E)}\ 64}$