Difference between revisions of "1989 AHSME Problems/Problem 1"

Revision as of 08:54, 19 February 2012

$(-1)^{5^2} + 1^{2^5} = (-1)^{25}+1^{32}=-1+1=0$ thus the answer is C.

Revision as of 21:44, 11 January 2012 (view source) Weird888 (talk \| contribs) (Created page with "(-1)^(5^2) + 1^(2^5) = (A) -7 (B) -2 (C) 0 (D) 1 (E) 57")		Revision as of 08:54, 19 February 2012 (view source) Ckorr2003 (talk \| contribs) Newer edit →
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−	(-1)^(5^2) + 1^(2^5) =	+	<math>(-1)^{5^2} + 1^{2^5} = (-1)^{25}+1^{32}=-1+1=0</math> thus the answer is C.
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−	(A) -~~7 (B~~) -~~2 (~~C~~) 0 (D) 1 (E) 57~~