Difference between revisions of "2011 AMC 8 Problems/Problem 14"

(Problem 14)
 
m (Added Solution and See Also headers)
Line 2: Line 2:
  
 
<math> \text{(A) } \dfrac7{18} \qquad\text{(B) } \dfrac7{15} \qquad\text{(C) } \dfrac{22}{45} \qquad\text{(D) } \dfrac12 \qquad\text{(E) } \dfrac{23}{45} </math>
 
<math> \text{(A) } \dfrac7{18} \qquad\text{(B) } \dfrac7{15} \qquad\text{(C) } \dfrac{22}{45} \qquad\text{(D) } \dfrac12 \qquad\text{(E) } \dfrac{23}{45} </math>
 +
 +
==Solution==
 +
 +
==See Also==
 +
{{AMC8 box|year=2011|num-b=13|num-a=15}}

Revision as of 17:46, 25 November 2011

There are $270$ students at Colfax Middle School, where the ratio of boys to girls is $5 : 4$. There are $180$ students at Winthrop Middle School, where the ratio of boys to girls is $4 : 5$. The two schools hold a dance and all students from both schools attend. What fraction of the students at the dance are girls?

$\text{(A) } \dfrac7{18} \qquad\text{(B) } \dfrac7{15} \qquad\text{(C) } \dfrac{22}{45} \qquad\text{(D) } \dfrac12 \qquad\text{(E) } \dfrac{23}{45}$

Solution

See Also

2011 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions