Difference between revisions of "2003 AMC 8 Problems/Problem 2"

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==Solution==
 
==Solution==
 
The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>.
 
The smallest prime factor is <math> 2 </math>, and since <math> 58 </math> is the only multiple of <math> 2 </math>, the answer is <math> \boxed{\mathrm{(C)}\ 58} </math>.
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{{AMC8 box|year=2003|num-b=1|num-a=3}}

Revision as of 08:36, 25 November 2011

Problem

Which of the following numbers has the smallest prime factor?

$\mathrm{(A)}\ 55 \qquad\mathrm{(B)}\ 57 \qquad\mathrm{(C)}\ 58 \qquad\mathrm{(D)}\ 59 \qquad\mathrm{(E)}\ 61$

Solution

The smallest prime factor is $2$, and since $58$ is the only multiple of $2$, the answer is $\boxed{\mathrm{(C)}\ 58}$.

2003 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AJHSME/AMC 8 Problems and Solutions