Difference between revisions of "2003 AMC 8 Problems/Problem 5"

Revision as of 08:33, 25 November 2011

If $20\%$ of a number is $12$ , what is $30\%$ of the same number?

$\textbf{(A)}\ 15\qquad\textbf{(B)}\ 18\qquad\textbf{(C)}\ 20\qquad\textbf{(D)}\ 24\qquad\textbf{(E)}\ 30$

$20\%$ of a number is equal to $\frac{1}{5}$ of that number. Let $n$ =the number

$\frac{1}{5}n = 12$ Multiply both sides by 5

$n = 60$

$30\%$ of $n$ is equal to $\frac{3}{10}n = \frac{3}{10}\cdot60 = 3\cdot6 = \boxed{\textbf{(B)}18}$

2003 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

Revision as of 08:33, 25 November 2011 (view source) AlcumusGuy (talk \| contribs) (Created page with "==Problem== If <math>20\%</math> of a number is <math>12</math>, what is <math>30\%</math> of the same number? <math> \textbf{(A)}\ 15\qquad\textbf{(B)}\ 18\qquad\textbf{(C)}\ ...")		Revision as of 08:33, 25 November 2011 (view source) AlcumusGuy (talk \| contribs) Newer edit →
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	<math>30\%</math> of <math>n</math> is equal to <math>\frac{3}{10}n = \frac{3}{10}\cdot60 = 3\cdot6 = \boxed{\textbf{(B)}18}</math>		<math>30\%</math> of <math>n</math> is equal to <math>\frac{3}{10}n = \frac{3}{10}\cdot60 = 3\cdot6 = \boxed{\textbf{(B)}18}</math>
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		+	{{AMC8 box\|year=2003\|num-b=4\|num-a=6}}