Difference between revisions of "1996 AHSME Problems/Problem 21"
Talkinaway (talk | contribs) (Created page with "==See also== {{AHSME box|year=1996|num-b=20|num-a=22}}") |
Talkinaway (talk | contribs) |
||
Line 1: | Line 1: | ||
+ | ==Problem== | ||
+ | |||
+ | Triangles <math>ABC</math> and <math>ABD</math> are isosceles with <math>AB=AC=BD</math>, and <math>BD</math> intersects <math>AC</math> at <math>E</math>. If <math>BD</math> is perpendicular to <math>AC</math>, then <math> \angle C+\angle D </math> is | ||
+ | |||
+ | <asy> | ||
+ | size(120); | ||
+ | pair B=origin, A=1*dir(70), M=foot(A, B, (3,0)), C=reflect(A, M)*B, E=foot(B, A, C), D=1*dir(20); | ||
+ | dot(A^^B^^C^^D^^E); | ||
+ | draw(A--D--B--A--C--B); | ||
+ | markscalefactor=0.005; | ||
+ | draw(rightanglemark(A, E, B)); | ||
+ | dot(A^^B^^C^^D^^E); | ||
+ | pair point=midpoint(A--M); | ||
+ | label("$A$", A, dir(point--A)); | ||
+ | label("$B$", B, dir(point--B)); | ||
+ | label("$C$", C, dir(point--C)); | ||
+ | label("$D$", D, dir(point--D)); | ||
+ | label("$E$", E, dir(point--E)); | ||
+ | </asy> | ||
+ | |||
+ | <math> \text{(A)}\ 115^\circ\qquad\text{(B)}\ 120^\circ\qquad\text{(C)}\ 130^\circ\qquad\text{(D)}\ 135^\circ\qquad\text{(E)}\ \text{not uniquely determined} </math> | ||
+ | |||
+ | ==Solution== | ||
+ | |||
+ | |||
==See also== | ==See also== | ||
{{AHSME box|year=1996|num-b=20|num-a=22}} | {{AHSME box|year=1996|num-b=20|num-a=22}} |
Revision as of 21:02, 19 August 2011
Problem
Triangles and are isosceles with , and intersects at . If is perpendicular to , then is
Solution
See also
1996 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |