Difference between revisions of "Law of Sines"
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− | Given a triangle with side lengths a, b, and c, opposite angles A, B, and C, and a circumcircle with radius R, <math>\frac{a}{\sin{A}}=\frac{b}{\sin{B}}=\frac{c}{\sin{C}}=2R</math>. | + | Given a [[triangle]] with side lengths a, b, and c, opposite angles A, B, and C, and a [[circumcircle]] with radius R, <math>\frac{a}{\sin{A}}=\frac{b}{\sin{B}}=\frac{c}{\sin{C}}=2R</math>. |
+ | |||
+ | ==See also== | ||
+ | * [[Trigonometry]] | ||
+ | * [[Trigonometric identities]] | ||
+ | * [[Geometry]] |
Revision as of 09:05, 23 June 2006
Given a triangle with side lengths a, b, and c, opposite angles A, B, and C, and a circumcircle with radius R, .