Difference between revisions of "1999 AHSME Problems/Problem 3"
(New page: To find the number halfway between <math>\frac{1}{8}</math> and <math>\frac{1}{10}</math>, simply take the arithmetic mean, which is <math>\frac{\frac{1}{8}+\frac{1}{10}}{2}=\frac{\frac{9...) |
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Thus the answer is choice <math>\boxed{E}.</math> | Thus the answer is choice <math>\boxed{E}.</math> | ||
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| + | ==See Also== | ||
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| + | {{AHSME box|year=1999|num-b=9|num-a=11}} | ||
Revision as of 12:49, 8 June 2011
To find the number halfway between 
and 
, simply take the arithmetic mean, which is
Thus the answer is choice 
See Also
| 1999 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
