Difference between revisions of "2011 AMC 10A Problems/Problem 1"
Aopsmath1012 (talk | contribs) (→Solution) |
m (→Solution) |
||
Line 6: | Line 6: | ||
== Solution == | == Solution == | ||
<math>30.5-30 = .5</math> hours which is <math>30</math> minutes. <math>30*10=300</math> cents which is <math>3</math> dollars. <math>100*.05=5</math> dollars. So finally <math>20+3+5=28</math> dollars. <math>\longrightarrow \boxed{\textbf{D}}</math> | <math>30.5-30 = .5</math> hours which is <math>30</math> minutes. <math>30*10=300</math> cents which is <math>3</math> dollars. <math>100*.05=5</math> dollars. So finally <math>20+3+5=28</math> dollars. <math>\longrightarrow \boxed{\textbf{D}}</math> | ||
+ | == See Also =={{AMC10 box|year=2011|ab=A|num-b=First Question|num-a=2}} |
Revision as of 09:57, 8 May 2011
Problem 1
A cell phone plan costs each month, plus ¢ per text message sent, plus ¢ for each minute used over hours. In January Michelle sent text messages and talked for hours. How much did she have to pay?
Solution
hours which is minutes. cents which is dollars. dollars. So finally dollars.
See Also
2011 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |