Difference between revisions of "2011 AIME I Problems/Problem 8"
(→Problem: ...Ok, now it) |
m (...'s really fixed.) |
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Line 3: | Line 3: | ||
− | <asy> | + | <center><asy> |
unitsize(1 cm); | unitsize(1 cm); | ||
pair translate; | pair translate; | ||
Line 51: | Line 51: | ||
dot("$X$",X[1],dir(-70)); | dot("$X$",X[1],dir(-70)); | ||
dot("$Y$",Y[1],dir(250)); | dot("$Y$",Y[1],dir(250)); | ||
− | dot("$Z$",Z[1],NE);</asy> | + | dot("$Z$",Z[1],NE);</asy></center> |
== See also == | == See also == | ||
{{AIME box|year=2011|n=I|num-b=7|num-a=9}} | {{AIME box|year=2011|n=I|num-b=7|num-a=9}} |
Revision as of 19:39, 3 April 2011
Problem
In triangle , , , and . Points and are on with on , points and are on with on , and points and are on with on . In addition, the points are positioned so that , , and . Right angle folds are then made along , , and . The resulting figure is placed on a level floor to make a table with triangular legs. Let be the maximum possible height of a table constructed from triangle whose top is parallel to the floor. Then can be written in the form , where and are relatively prime positive integers and is a positive integer that is not divisible by the square of any prime. Find .
See also
2011 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |