Difference between revisions of "2011 AMC 10A Problems/Problem 13"
Thedrummer (talk | contribs) (Created page with '==Problem 13== How many even integers are there between 200 and 700 whose digits are all different and come from the set {1,2,5,7,8,9}? <math>\text{(A)}\,12 \qquad\text{(B)}\,20…') |
|||
Line 3: | Line 3: | ||
<math>\text{(A)}\,12 \qquad\text{(B)}\,20 \qquad\text{(C)}\,72 \qquad\text{(D)}\,120 \qquad\text{(E)}\,200</math> | <math>\text{(A)}\,12 \qquad\text{(B)}\,20 \qquad\text{(C)}\,72 \qquad\text{(D)}\,120 \qquad\text{(E)}\,200</math> | ||
+ | |||
+ | == Solution == | ||
+ | |||
+ | We split up into cases of the hundreds digits being <math>2</math> or <math>5</math>. If the hundred digits is <math>2</math>, then the units digits must be <math>8</math> in order for the number to be even and then there are <math>4</math> remaining choices (<math>1,5,7,9</math>) for the tens digit, giving <math>1 \times 1 \times 4=4</math> possibilities. Similarly, there are <math>1 \times 2 \times 4=8</math> possibilities for the <math>5</math> case, giving a total of \boxed{12 \ \mathbf{(A)}} possibilities. |
Revision as of 14:08, 14 February 2011
Problem 13
How many even integers are there between 200 and 700 whose digits are all different and come from the set {1,2,5,7,8,9}?
Solution
We split up into cases of the hundreds digits being or . If the hundred digits is , then the units digits must be in order for the number to be even and then there are remaining choices () for the tens digit, giving possibilities. Similarly, there are possibilities for the case, giving a total of \boxed{12 \ \mathbf{(A)}} possibilities.