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Difference between revisions of "2007 AMC 8 Problems/Problem 1"

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<math>\frac{48 + x}{6} = 10</math>   
 
<math>\frac{48 + x}{6} = 10</math>   
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<math>48 + x = 60</math>   
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\<math>48 + x = 60</math>   
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<math>x = 12</math>
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\<math>x = 12</math>
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So, <math>\boxed{D}</math>
+
\So, <math>\boxed{D}</math>

Revision as of 14:40, 15 February 2010

Problem

Theresa's parents have agreed to buy her tickets to see her favorite band if she spends an average of $10$ hours per week helping around the house for $6$ weeks. For the first $5$ weeks she helps around the house for $8$, $11$, $7$, $12$ and $10$ hours. How many hours must she work for the final week to earn the tickets?

$\mathrm{(A)}\ 9 \qquad\mathrm{(B)}\ 10 \qquad\mathrm{(C)}\ 11 \qquad\mathrm{(D)}\ 12 \qquad\mathrm{(E)}\ 13$

Solution

Let $x$ be the number of hours she must work for the final week. We are looking for the average, so $\frac{8 + 11 + 7 + 12 + 10 + x}{6} = 10$

Solving gives:

$\frac{48 + x}{6} = 10$ \$48 + x = 60$ \$x = 12$ \So, $\boxed{D}$

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