Difference between revisions of "2001 AMC 12 Problems/Problem 10"
(New page: == Problem == The plane is tiled by congruent squares and congruent pentagons as indicated. The percent of the plane that is enclosed by the pentagons is closest to <math> \text{(A) }50 ...) |
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If the side of the small square is <math>a</math>, then the area of the tile is <math>9a^2</math>, with <math>4a^2</math> covered by squares and <math>5a^2</math> by pentagons. | If the side of the small square is <math>a</math>, then the area of the tile is <math>9a^2</math>, with <math>4a^2</math> covered by squares and <math>5a^2</math> by pentagons. | ||
− | Hence exactly <math>5/9</math> of any tile are covered by pentagons, and therefore pentagons cover <math>5/9</math> of the plane. When expressed as a percentage, this is <math>55.\overline{5}\%</math>, and the closest integer to this value is <math>\boxed{ | + | Hence exactly <math>5/9</math> of any tile are covered by pentagons, and therefore pentagons cover <math>5/9</math> of the plane. When expressed as a percentage, this is <math>55.\overline{5}\%</math>, and the closest integer to this value is <math>56</math>. <math>\boxed{\mathrm{D}}</math> |
== See Also == | == See Also == | ||
{{AMC12 box|year=2001|num-b=9|num-a=11}} | {{AMC12 box|year=2001|num-b=9|num-a=11}} |
Revision as of 16:33, 23 August 2009
Problem
The plane is tiled by congruent squares and congruent pentagons as indicated. The percent of the plane that is enclosed by the pentagons is closest to
Solution
Consider any single tile:
If the side of the small square is , then the area of the tile is , with covered by squares and by pentagons. Hence exactly of any tile are covered by pentagons, and therefore pentagons cover of the plane. When expressed as a percentage, this is , and the closest integer to this value is .
See Also
2001 AMC 12 (Problems • Answer Key • Resources) | |
Preceded by Problem 9 |
Followed by Problem 11 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |