Difference between revisions of "2005 AMC 12B Problems/Problem 10"
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== Problem == | == Problem == | ||
| + | The first term of a sequence is 2005. Each succeeding term is the sum of the cubes of the digits of the previous terms. What is the 2005th term of the sequence? | ||
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| + | <math>\mathrm{(A)}\ {{{29}}} \qquad \mathrm{(B)}\ {{{55}}} \qquad \mathrm{(C)}\ {{{85}}} \qquad \mathrm{(D)}\ {{{133}}} \qquad \mathrm{(E)}\ {{{250}}}</math> | ||
== Solution == | == Solution == | ||
Revision as of 21:10, 29 July 2009
Problem
The first term of a sequence is 2005. Each succeeding term is the sum of the cubes of the digits of the previous terms. What is the 2005th term of the sequence?
