Difference between revisions of "2009 IMO Problems/Problem 1"
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== Solution == | == Solution == |
Revision as of 05:23, 23 July 2009
Problem
Let be a positive integer and let be distinct integers in the set such that divides for . Prove that doesn't divide .
Author: Ross Atkins, Australia
--Bugi 10:23, 23 July 2009 (UTC)Bugi
Solution
Let such that and . Suppose divides . Note implies and hence . Similarly one has for all 's, in particular, and force . Now gives , similarly one has for all 's, that is 's satisfy and , but there should be at most one such integer satisfies them within the range of for and . A contradiction!!!
Solution by ychjae