Difference between revisions of "2000 AMC 10 Problems/Problem 2"

m (Solution)
m (See Also)
Line 13: Line 13:
 
==See Also==
 
==See Also==
  
{{AMC10 box|year=2000|before=First question|num-a=2}}
+
{{AMC10 box|year=2000|num-b=1|num-a=3}}

Revision as of 17:39, 8 January 2009

Problem

$2000\left(2000^{2000}\right)=$

$\mathrm{(A)}\ {2000}^{2001} \qquad \mathrm{(B)}\ {4000}^{2000} \qquad \mathrm{(C)}\ {2000}^{4000} \qquad \mathrm{(D)}\ {4,000,000}^{2000} \qquad\mathrm{(E)}\ {2000}^{4,000,000}$

Solution

$2000 \cdot 2000^{2000}=2000^1 \cdot 2000^{2000}=2000^{2000+1}=2000^{2001}$.

$\boxed{\text{A}}$

See Also

2000 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions