Difference between revisions of "2002 AMC 10A Problems/Problem 1"

(New page: ==Problem== The ratio <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> is closest to which of the following numbers? <math>\text{(A)}\ 0.1 \qquad \text{(B)}\ 0.2 \qquad \text{...)
 
(see also)
Line 6: Line 6:
 
==Solution==
 
==Solution==
 
We factor <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> as <math>\frac{10^{2000}(1+100)}{10^{2001}(1+1)}=\frac{101}{20}</math>. As <math>\frac{101}{20}=5.05</math>, our answer is <math>\text{(D)}\ 5 \qquad</math>.
 
We factor <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> as <math>\frac{10^{2000}(1+100)}{10^{2001}(1+1)}=\frac{101}{20}</math>. As <math>\frac{101}{20}=5.05</math>, our answer is <math>\text{(D)}\ 5 \qquad</math>.
 +
 +
==See Also==
 +
{{AMC10 box|year=2002|ab=A|before=First question|num-a=2}}
 +
 +
[[Category:Introductory Algebra Problems]]

Revision as of 16:59, 26 December 2008

Problem

The ratio $\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}$ is closest to which of the following numbers?

$\text{(A)}\ 0.1 \qquad \text{(B)}\ 0.2 \qquad \text{(C)}\ 1 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 10$

Solution

We factor $\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}$ as $\frac{10^{2000}(1+100)}{10^{2001}(1+1)}=\frac{101}{20}$. As $\frac{101}{20}=5.05$, our answer is $\text{(D)}\ 5 \qquad$.

See Also

2002 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions