Difference between revisions of "Summation"

Revision as of 21:56, 19 November 2008

A summation is the sum of a number of terms (addends). Summations are often written using sigma notation $\left(\sum \right)$ .

Definition

For $b\ge a$ , and a set $c$ (or any other algebraic structure), $\sum_{i=a}^{b}c_i=c_a+c_{a+1}+c_{a+2}...+c_{b-1}+c_{b}$ . Here $i$ refers to the index of summation, $a$ is the lower bound, and $b$ is the upper bound.

As an example, $\sum_{i=3}^6 i^3 = 3^3 + 4^3 + 5^3 + 6^3$ . Note that if $a>b$ , then the sum is $0$ .

Quite often, sigma notation is used slightly different format to denote certain sums. For example, $\sum_{cyc}$ refers to a cyclic sum, and $\sum_{a,b \in S}$ refers to all subsets $a, b$ which are in $S$ . Usually, the bottom of the sigma contains a logical condition, as in $\sum_{i|n}^{n} i$ , where the sum only includes the terms $i$ which divide into $n$ .

Identities

$\sum_{i=a}^{b}(f(i)+g(i))=\sum_{i=a}^{b}f(i)+\sum_{i=a}^{b}g(i)$
$\sum_{i=a}^{b}c\cdot f(i)=c\cdot \sum_{i=a}^{b}f(i)$
$\sum_{i=1}^{n} i= \frac{n(n+1)}{2}$ , and in general $\sum_{i=a}^{b} i= \frac{(b-a+1)(a+b)}{2}$
$\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6}$
$\sum_{i=1}^{n} i^3 = \left(\sum_{i=1}^{n} i\right)^2 = \left(\frac{n(n+1)}{2}\right)^2$
$\sum_{i=0}^{n} x^n = \frac{x^{n+1}-1}{x-1}$ , and in general $\sum_{i=a}^{b} c^i = \frac{c^{b+1}-c^a}{c-1}$
$\sum_{i=0}^{n} {n\choose i} = 2^n$
$\sum_{i,j}^{n} = \sum_i^n \sum_j^n$

Problems

Introductory

Evaluate the following sums:
- $\sum_{i=1}^{20} i$
- $\sum_{i=5}^{15} i + 1$
- $\sum_{i=1}^{9} {10\choose i}$

Intermediate

The nine horizontal and nine vertical lines on an $8\times8$ checkerboard form $r$ rectangles, of which $s$ are squares. The number $s/r$ can be written in the form $m/n,$ where $m$ and $n$ are relatively prime positive integers. Find $m + n.$ (1997 AIME, #2)

@@ Line 9: / Line 9: @@
 ==Identities==
-*<math>\sum_{i=a}^{b}f(i)+g(i)=\sum_{i=a}^{b}f(i)+\sum_{i=a}^{b}g(i)</math>
+*<math>\sum_{i=a}^{b}(f(i)+g(i))=\sum_{i=a}^{b}f(i)+\sum_{i=a}^{b}g(i)</math>
 *<math>\sum_{i=a}^{b}c\cdot f(i)=c\cdot \sum_{i=a}^{b}f(i)</math>
 *<math>\sum_{i=1}^{n} i= \frac{n(n+1)}{2}</math>, and in general <math>\sum_{i=a}^{b} i= \frac{(b-a+1)(a+b)}{2}</math>

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