Difference between revisions of "2007 Alabama ARML TST Problems/Problem 1"
(New page: ==Problem== Compute: <math>\sqrt{2000\cdot 2007\cdot 2008\cdot 2015+784}.</math> ==Solution== <math>2000(2000+7)(2000+8)(2000+15)+784=(2000^2+15\cdot 2000+56)(2000^2+15\cdot 2000)+28^2=(2...) |
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<math>2000(2000+7)(2000+8)(2000+15)+784=(2000^2+15\cdot 2000+56)(2000^2+15\cdot 2000)+28^2=(2000^2+15\cdot 2000+28)(2000^2+15\cdot 2000+28)-28^2+28^2</math> | <math>2000(2000+7)(2000+8)(2000+15)+784=(2000^2+15\cdot 2000+56)(2000^2+15\cdot 2000)+28^2=(2000^2+15\cdot 2000+28)(2000^2+15\cdot 2000+28)-28^2+28^2</math> | ||
| − | Thus < | + | Thus <math>\sqrt{2000\cdot 2007\cdot 2008\cdot 2015+784}=\boxed{4030028}</math> |
==See also== | ==See also== | ||
Revision as of 12:18, 17 June 2008
Problem
Compute: 
Solution
Thus 
