Revision as of 12:27, 3 May 2008

Day 1

Problem 1

Determine all composite positive integers $n$ for which it is possible to arrange all divisors of $n$ that are greater than 1 in a circle so that no two adjacent divisors are relatively prime.

Solution

Problem 2

Prove that the system $\begin{align*} x^6+x^3+x^3y+y & = 147^{157} \\ x^3+x^3y+y^2+y+z^9 & = 157^{147} \end{align*}$ has no solutions in integers $x$ , $y$ , and $z$ .

Solution

Problem 3

Let $ABC$ be an acute-angled triangle, and let $P$ and $Q$ be two points on side $BC$ . Construct point $C_1$ in such a way that convex quadrilateral $APBC_1$ is cyclic, $QC_1 \parallel CA$ , and $C_1$ and $Q$ lie on opposite sides of line $AB$ . Construct point $B_1$ in such a way that convex quadrilateral $APCB_1$ is cyclic, $QB_1 \parallel BA$ , and $B_1$ and $Q$ lie on opposite sides of line $AC$ . Prove that points $B_1, C_1,P$ , and $Q$ lie on a circle.

Solution

Day 2

Problem 4

This problem needs a solution. If you have a solution for it, please help us out by adding it.

Solution

Problem 5

This problem needs a solution. If you have a solution for it, please help us out by adding it.

Solution

Problem 6

This problem needs a solution. If you have a solution for it, please help us out by adding it.

Solution

Resources

2005 USAMO (Problems • Resources)
Preceded by 2004 USAMO	Followed by 2006 USAMO
1 • 2 • 3 • 4 • 5 • 6
All USAMO Problems and Solutions

@@ Line 44: / Line 44: @@
 * [http://www.unl.edu/amc/e-exams/e8-usamo/e8-1-usamoarchive/2006-ua/2006usamoS.pdf 2005 USAMO Solutions]
 * [http://www.artofproblemsolving.com/Forum/resources.php?c=182&cid=27&year=2005 USAMO Problems on the Resources page]
-{{USAMO newbox|year=2006|before=[[2005 USAMO]]|after=2007 USAMO}}
+{{USAMO newbox|year=2005|before=[[2004 USAMO]]|after=2006 USAMO}}

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Difference between revisions of "2005 USAMO Problems"

Revision as of 12:27, 3 May 2008

Contents

Day 1

Problem 1

Problem 2

Problem 3

Day 2

Problem 4

Problem 5

Problem 6

Resources