Difference between revisions of "2006 AMC 10B Problems/Problem 3"

(Solution 2)
(Solution)
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== Solution ==
 
== Solution ==
 
Let <math>x</math> be the number of points scored by the Cougars, and <math>y</math> be the number of points scored by the Panthers. The problem is asking for the value of <math>y</math>.  
 
Let <math>x</math> be the number of points scored by the Cougars, and <math>y</math> be the number of points scored by the Panthers. The problem is asking for the value of <math>y</math>.  
<cmath>\begin{align*}
+
<math></math>\begin{align*}
 
x+y &= 34 \\
 
x+y &= 34 \\
 
x-y &= 14 \\
 
x-y &= 14 \\
 
2x &= 48 \\
 
2x &= 48 \\
 
x &= 24 \\
 
x &= 24 \\
y &= \boxed{\textbf{(A) }10} \\
+
The answer is <math>(A) 10</math>
\end{align*}</cmath>
 
  
 
== Solution 2 ==
 
== Solution 2 ==

Revision as of 14:50, 21 February 2025

Problem

A football game was played between two teams, the Cougars and the Panthers. The two teams scored a total of $34$ points, and the Cougars won by a margin of $14$ points. How many points did the Panthers score?

$\textbf{(A) } 10\qquad \textbf{(B) } 14\qquad \textbf{(C) } 17\qquad \textbf{(D) } 20\qquad \textbf{(E) } 24$

Solution

Let $x$ be the number of points scored by the Cougars, and $y$ be the number of points scored by the Panthers. The problem is asking for the value of $y$. $$ (Error compiling LaTeX. Unknown error_msg)\begin{align*} x+y &= 34 \\ x-y &= 14 \\ 2x &= 48 \\ x &= 24 \\ The answer is $(A) 10$

Solution 2

$c$ is the amount the Cougars scored and $p$ is the score for Panthers. Since the Cougars won by 14 points, $c = p + 14$. Using substitution, $2p + 14 = 34$, $2p = 20$, and then $p = 10$.

p &= \boxed{\textbf{(A) }10} \\ \end{align*}$$ (Error compiling LaTeX. Unknown error_msg)

-- leafy

See Also

2006 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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