Difference between revisions of "Median"

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== Median of a distribution ==
 
== Median of a distribution ==
=== Median of a discrete distribution ===
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=== Discrete distributions ===
  
 
If <math>F</math> is a [[discrete distribution]], whose [[support]] is a subset of a [[countable]] set <math>{x_1, x_2, x_3, ...}</math>, with <math>x_i < x_{i+1}</math> for all positive integers <math>i</math>, the median of <math>F</math> is any point lying between <math>x_i</math> and <math>x_{i+1}</math> where <math>F(x_i)\leq\frac12</math> and <math>F(x_{i+1})\geq\frac12</math>. If <math>F(x_i)=\frac12</math> for some <math>i</math>, <math>x_i</math> is defined to be the median of <math>F</math>.
 
If <math>F</math> is a [[discrete distribution]], whose [[support]] is a subset of a [[countable]] set <math>{x_1, x_2, x_3, ...}</math>, with <math>x_i < x_{i+1}</math> for all positive integers <math>i</math>, the median of <math>F</math> is any point lying between <math>x_i</math> and <math>x_{i+1}</math> where <math>F(x_i)\leq\frac12</math> and <math>F(x_{i+1})\geq\frac12</math>. If <math>F(x_i)=\frac12</math> for some <math>i</math>, <math>x_i</math> is defined to be the median of <math>F</math>.
  
=== Median of a continuous distribution ===
+
=== Continuous distributions ===
  
 
If <math>F</math> is a [[continuous distribution]], whose support is a subset of the real numbers, the median of <math>F</math> is defined to be the <math>x</math> such that <math>F(x)=\frac12</math>. Clearly, if <math>F</math> has a [[density]] <math>f</math>, this is equivalent to saying <math>\int^x_{-\infty}f = \frac12</math>.
 
If <math>F</math> is a [[continuous distribution]], whose support is a subset of the real numbers, the median of <math>F</math> is defined to be the <math>x</math> such that <math>F(x)=\frac12</math>. Clearly, if <math>F</math> has a [[density]] <math>f</math>, this is equivalent to saying <math>\int^x_{-\infty}f = \frac12</math>.
  
 
== Problems ==
 
== Problems ==
===Pre-introductory===
 
Find the median of <math>\{3, 4, 5, 15, 9\}</math>.
 
===Introductory===
 
[[2000 AMC 12 Problems/Problem 14]]
 
  
[[2004 AMC 12A Problems/Problem 10]]
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=== Introductory ===
  
===Intermediate===
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*Find the median of <math>\{3, 4, 5, 15, 9\}</math>.
===Olympiad===
+
*[[2000 AMC 12 Problems/Problem 14]]
 +
*[[2004 AMC 12A Problems/Problem 10]]
  
{{problems}}
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=== Intermediate ===
 +
=== Olympiad ===
 +
 
 +
{{problem}}
  
 
== Video ==
 
== Video ==
 +
 
[//youtu.be/TkZvMa30Juo Video]
 
[//youtu.be/TkZvMa30Juo Video]
  

Revision as of 16:14, 19 February 2025

This article is about the median used in statistics. For other medians, check Median (disambiguation).

This article is about the median used in statistics. For other medians, check Median (disambiguation).

A median is a measure of central tendency used frequently in statistics.

Median of a data set

The median of a finite set of real numbers $\{X_1, ..., X_k\}$ is defined to be $x$ such that $\sum_{i=1}^k |X_i - x| = \min_y \sum_{i=1}^k |X_i - y|$. This turns out to be $X_{(\frac{k+1}2)}$ when $k$ is odd. When $k$ is even, all points between $X_{(\frac{k}2)}$ and $X_{(\frac{k}2 + 1)}$ are medians. If we have to specify one median we conventionally take $\frac{X_{(\frac{k}2)} + X_{(\frac{k}2 + 1)}}2$. (Here $X_{(i)}, i \in \{1,...,k\}$ denotes the $k^{th}$ order statistic.) For example, the median of the set $\{2, 3, 5, 7, 11, 13, 17\}$ is 7.

Median of a distribution

Discrete distributions

If $F$ is a discrete distribution, whose support is a subset of a countable set ${x_1, x_2, x_3, ...}$, with $x_i < x_{i+1}$ for all positive integers $i$, the median of $F$ is any point lying between $x_i$ and $x_{i+1}$ where $F(x_i)\leq\frac12$ and $F(x_{i+1})\geq\frac12$. If $F(x_i)=\frac12$ for some $i$, $x_i$ is defined to be the median of $F$.

Continuous distributions

If $F$ is a continuous distribution, whose support is a subset of the real numbers, the median of $F$ is defined to be the $x$ such that $F(x)=\frac12$. Clearly, if $F$ has a density $f$, this is equivalent to saying $\int^x_{-\infty}f = \frac12$.

Problems

Introductory

Intermediate

Olympiad

This problem has not been edited in. Help us out by adding it.

Video

Video

See Also

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