Difference between revisions of "Division of Zero by Zero"

Revision as of 16:59, 14 February 2025

Division of Zero by Zero, is an unexplained mystery, since decades in the field of mathematics and is indeterminate. This is been a great mystery to solve for any mathematician and rather to use limits to set value of Zero by Zero in differential calculus one of the Indian-Mathematical-Scientist Jyotiraditya Jadhav has got correct solution set for the process with a proof.

About Zero and its Operators

Discovery

The first recorded zero appeared in Mesopotamia around 3 B.C. The Mayans invented it independently circa 4 A.D. It was later devised in India in the mid-fifth century, spread to Cambodia near the end of the seventh century, and into China and the Islamic countries at the end of the eighth

Operators

"Zero and its operation are first defined by [Hindu astronomer and mathematician] Brahmagupta in 628," said Gobets. He developed a symbol for zero: a dot underneath numbers.

@@ Line 8: / Line 8: @@
 === Operators ===
 "'''Zero''' and its '''operation''' are first '''defined''' by [Hindu astronomer and mathematician] Brahmagupta in 628," said Gobets. He developed a symbol for '''zero''': a dot underneath numbers.
-== Detailed proof ==
-We will form two solution sets (namely set(A) and set(B))
-Solution set(A):
-If we divide zero by zero then we have <math>0/0</math>.
-We can write the 0 in the numerator as <math>(1-1)</math> and in the denominator as <math>(1-1)</math>, which yields <math>(1-1)/(1-1)=1</math>.
-We can then write the 0 in the numerator as <math>(2-2)</math> and in the denominator as <math>(1-1)</math>, which yields <math>(2-2)/(1-1)=2(1-1)/(1-1)</math>                                                               [Taking 2 as common]
-<math>=2</math>
-We can even write the 0 in the numerator as <math>( \infty- \infty) </math> and in the denominator as <math>(1-1)</math>,
-=<math>( \infty-\infty)/(1-1) </math>
-= <math> \infty(1-1)/(1-1) </math>                                                             [Taking <math> \infty</math> as common]
-= <math> \infty</math>
-So, the solution set(A) comprises of all real numbers.
-set(A) = <math>\{- \infty.....-3,-2,-1,0,1,2,3.... \infty\}  </math>
-Solution set(B):
-If we divide zero by zero then
-<math>0/0</math>
-We know that the actual equation is <math>0^1/0^1 </math>
-=<math>0^1/0^1 </math>
-= 0^(1-1)                                                                              [Laws of Indices, <math>a^m/a^n = a^{m-n} </math>]
-= <math>0^0 </math>
-=<math>1 </math>                                                                                        [https://brilliant.org/wiki/what-is-00| Already proven]
-So, the solution set(B) is a singleton set
-set(B) =<math>\{1\} </math>
-Now we can get a finite value to division of <math>0/0 </math> by taking the intersection of both the solution sets.
-Let the final solution set be <math>F </math>
-<math>A\bigcap B </math> = <math>F </math>
-<math>\{- \infty.....-3,-2,-1,0,1,2,3....\infty\}  </math> <math>\bigcap </math> <math>\{1\} </math>
-<math>F </math> = <math>\{1\} </math>
-Hence proving <math>0/0 =1 </math>
-{{stub}}

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Difference between revisions of "Division of Zero by Zero"

Revision as of 16:59, 14 February 2025

About Zero and its Operators

Discovery

Operators