Difference between revisions of "Jadhav Quadratic Formula"

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Jadhav Quadratic Formula, '''evaluates accurate values''' of numbers '''lying on x-axis''' of the co-ordinate plane corresponding to the respective '''y-axis points.''' Derived by Indian-Mathematical Scholar
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The '''Jadhav Quadratic Formula''' finds all values of <math>x</math> for a given value of <math>y</math> in any [[quadratic equation]] <math>ax^2+bx+c</math>. It is named after mathematician [[Jyotiraditya Jadhav]].
  
== '''Formula''' ==
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== Statement ==
If we are given the points of y-axis with the quadratic equation it followed then we can find the respective x-axis points by:
 
  
<math>x = {-b \pm \surd b^2 - 4a (c-y)}/2a</math>
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For any given value of <math>y</math> in quadratic equation <math>y=ax^2+bx+c</math>, we can find its respective values for <math>x</math>
  
== Requirements ==
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<cmath>x = \frac{-b \pm \sqrt{b^2-4a(c-y)}}{2a}</cmath>
For this formula to function we should have the quadratic equation along with given y-axis point and can get the 2 corresponding points on the x-axis.
 
  
== Nomenclature ==
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=== Derivation ===
  
* '''b: Coefficient of <math>x</math>.'''
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We have the quadratic equation <math>y = ax^2+bx+c</math>, which can be rewritten as <math>ax^2+bx+(c-y) = 0</math>. From the [[quadratic formula]], we have <math>x = \frac{-b \pm \sqrt{b^2-4a(c-y)}}{2a}</math>, as desired.
* '''a: Coefficient of <math>x^2</math>.'''
 
* '''c: Constant term of equation.'''
 
* '''y: The given y-axis point.'''
 
  
== Historical Note ==
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== See Also ==
This Formula is made by '''[[Jyotiraditya Jadhav|Jyotiraditya Abhay Jadhav]],''' an Indian Mathematical-Scientist.
 
  
== Derivation ==
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* [[Quadratic Equation]]
Let the quadratic equation be : <math>ax^2+bx+c </math>
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* [[Quadratic Formula]]
  
Now at some given value of x the function of graph will give the value for point lying on y-axis
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{{stub}}
 
 
So, we can equate
 
 
 
<math>ax^2+bx+c=y </math>
 
 
 
<math>x^2+bx/a+c/a = y/a  </math> (dividing all terms by a)
 
 
 
<math>{x^{2}+2bx/2a+b^2/4a^2+c/a=y/a+b^2/4a^2} </math> (adding <math>{b^2/4a^2} </math> on both sides)
 
 
 
<math>[{x+b/2a}]^{2}+c/a=y/a+b^{2}/4a^{2}
 
</math>
 
 
 
<math>[{x+b/2a}]^{2}=y/a+b^{2}/4a^{2}-c/a
 
</math>
 
 
 
<math>x+b/2a=\pm\surd[y/a+b^{2}/4a^{2}-c/a]
 
</math>
 
 
 
<math>x+b/2a=\pm\surd[4ay+b^{2}-4ac]/\surd\left\vert 4a^2 \right\vert 
 
</math>
 
 
 
<math>x=-b/2a\pm\surd[4ay+b^{2}-4ac]/\surd\left\vert 4a^2 \right\vert 
 
</math>
 
 
 
<math>x=[-b\pm\surd b^{2}-4a(c-y)]/2a 
 
</math>
 
 
 
Deriving the Jadhav Quadratic Formula.
 
[[Category:Jyotiraditya Jadhav]]
 
[[Category:Mathematical concepts]]
 
__INDEX__
 

Revision as of 09:22, 2 February 2025

The Jadhav Quadratic Formula finds all values of $x$ for a given value of $y$ in any quadratic equation $ax^2+bx+c$. It is named after mathematician Jyotiraditya Jadhav.

Statement

For any given value of $y$ in quadratic equation $y=ax^2+bx+c$, we can find its respective values for $x$

\[x = \frac{-b \pm \sqrt{b^2-4a(c-y)}}{2a}\]

Derivation

We have the quadratic equation $y = ax^2+bx+c$, which can be rewritten as $ax^2+bx+(c-y) = 0$. From the quadratic formula, we have $x = \frac{-b \pm \sqrt{b^2-4a(c-y)}}{2a}$, as desired.

See Also

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