Difference between revisions of "2025 AMC 8 Problems/Problem 8"
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==Solution== | ==Solution== | ||
Observe that since the six squares on the net are congruent, each of them has area <math>\frac{18}{6}=3</math>. Hence, the side length of the cube is <math>\sqrt{3}</math>. Its volume is then <math>(\sqrt{3})^3=\boxed{\textbf{(A)}~3\sqrt{3}}</math>. ~cxsmi | Observe that since the six squares on the net are congruent, each of them has area <math>\frac{18}{6}=3</math>. Hence, the side length of the cube is <math>\sqrt{3}</math>. Its volume is then <math>(\sqrt{3})^3=\boxed{\textbf{(A)}~3\sqrt{3}}</math>. ~cxsmi | ||
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| + | ==Vide Solution 1 by SpreadTheMathLove== | ||
| + | https://www.youtube.com/watch?v=jTTcscvcQmI | ||
Revision as of 22:15, 29 January 2025
Problem
Isaiah cuts open a cardboard cube along some of its edges to form the flat shape shown on the right, which has an area of 18 square centimeters. What is the volume of the cube in cubic centimeters?
Solution
Observe that since the six squares on the net are congruent, each of them has area 
. Hence, the side length of the cube is 
. Its volume is then 
. ~cxsmi
