Difference between revisions of "2025 AMC 8 Problems/Problem 6"

m (Protected "2025 AMC 8 Problems/Problem 6" ([Edit=Allow only administrators] (expires 17:59, 29 January 2025 (UTC)) [Move=Allow only administrators] (expires 17:59, 29 January 2025 (UTC))))
Line 1: Line 1:
The 2025 AMC 8 is not held yet. Please do not post false problems.
+
Sekou writes the numbers <math>15, 16, 17, 18, 19.</math> After he erases one of his numbers, the sum of the remaining four numbers is a multiple of <math>4.</math> Which number did he erase?
 +
 
 +
A)15 B)16 C)17 D)18 E)19
 +
 
 +
Solution 1
 +
 
 +
First, we sum the <math>5</math> numbers to get <math>85</math>. The number subtracted therefore must be 1 more than a multiple of 4. Thus, the answer is 17.
 +
~Gavin_Deng

Revision as of 19:51, 29 January 2025

Sekou writes the numbers $15, 16, 17, 18, 19.$ After he erases one of his numbers, the sum of the remaining four numbers is a multiple of $4.$ Which number did he erase?

A)15 B)16 C)17 D)18 E)19

Solution 1

First, we sum the $5$ numbers to get $85$. The number subtracted therefore must be 1 more than a multiple of 4. Thus, the answer is 17. ~Gavin_Deng