Difference between revisions of "2025 AMC 8 Problems/Problem 6"
m (Protected "2025 AMC 8 Problems/Problem 6" ([Edit=Allow only administrators] (expires 17:59, 29 January 2025 (UTC)) [Move=Allow only administrators] (expires 17:59, 29 January 2025 (UTC)))) |
Gavin deng (talk | contribs) |
||
Line 1: | Line 1: | ||
− | The | + | Sekou writes the numbers <math>15, 16, 17, 18, 19.</math> After he erases one of his numbers, the sum of the remaining four numbers is a multiple of <math>4.</math> Which number did he erase? |
+ | |||
+ | A)15 B)16 C)17 D)18 E)19 | ||
+ | |||
+ | Solution 1 | ||
+ | |||
+ | First, we sum the <math>5</math> numbers to get <math>85</math>. The number subtracted therefore must be 1 more than a multiple of 4. Thus, the answer is 17. | ||
+ | ~Gavin_Deng |
Revision as of 19:51, 29 January 2025
Sekou writes the numbers After he erases one of his numbers, the sum of the remaining four numbers is a multiple of Which number did he erase?
A)15 B)16 C)17 D)18 E)19
Solution 1
First, we sum the numbers to get . The number subtracted therefore must be 1 more than a multiple of 4. Thus, the answer is 17. ~Gavin_Deng