Difference between revisions of "2025 AMC 8 Problems/Problem 4"

Revision as of 19:24, 29 January 2025

Lucius is counting backward by $7$ s. His first three numbers are $100$ , $93$ , and $86$ . What is his $10$ th number?

Solution

By the formula for the $n$ th term of an arithmetic sequence, we get that the answer is $a+d(n-1)$ where $a=100, d=-7$ and $n=10$ which is $100 - 7(10 - 1) = \boxed{\text{(B)\ 37}}$ .

~Soupboy0

@@ Line 1: / Line 1: @@
-The 2025 AMC 8 is not held yet. '''Please do not post false problems.'''
+Lucius is counting backward by <math>7</math>s. His first three numbers are <math>100</math>, <math>93</math>, and <math>86</math>. What is his <math>10</math>th number?
+==Solution==
+By the formula for the <math>n</math>th term of an arithmetic sequence, we get that the answer is <math>a+d(n-1)</math> where <math>a=100, d=-7</math> and <math>n=10</math> which is <math>100 - 7(10 - 1) = \boxed{\text{(B)\ 37}}</math>.
+~Soupboy0

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Difference between revisions of "2025 AMC 8 Problems/Problem 4"

Revision as of 19:24, 29 January 2025

Solution