Difference between revisions of "Laplace transform"

(Created page with "The '''Laplace Transform''' of a function is a linear transformation from the space of <math>\Re \to \Re</math> (<math>\Re</math> is the space of integratable functions) d...")
 
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The '''Laplace Transform''' of a function is a [[linear transformation]] from the space of <math>\Re \to \Re</math> (<math>\Re</math> is the space of integratable functions) defined as  
 
The '''Laplace Transform''' of a function is a [[linear transformation]] from the space of <math>\Re \to \Re</math> (<math>\Re</math> is the space of integratable functions) defined as  
  
<cmath>\pound {f} (s) = F(s) = \int _{0} ^ {\infty} e^{-st} f(t) dt</cmath>
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<cmath>\pounds \{ f \} (s) = F(s) = \int _{0} ^ {\infty} e^{-st} f(t) dt</cmath>
  
 
==Uses==
 
==Uses==
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We first take the Laplace Transform of the equation, then solve the resulting algebra equation for <math>Y(s)</math>, and then take the inverse Laplace Transform of <math>Y(s)</math> to get <math>y</math>.
 
We first take the Laplace Transform of the equation, then solve the resulting algebra equation for <math>Y(s)</math>, and then take the inverse Laplace Transform of <math>Y(s)</math> to get <math>y</math>.
  
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==Example==
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Solve the differential equation
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<cmath>y''+y= H(t-5)</cmath>
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, where <math>H(t)</math> is the Heaviside function, defined as
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<cmath>H(x)= \begin{cases} x^2 &\text{if } x \ge 0 \\ x &\text{if } x < 0 \end{cases}</cmath>
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''Solution:''
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We take the Laplace transe
 
==See Also==
 
==See Also==
 
*[[Differential equations]]
 
*[[Differential equations]]

Revision as of 21:01, 11 January 2025

The Laplace Transform of a function is a linear transformation from the space of $\Re \to \Re$ ($\Re$ is the space of integratable functions) defined as

\[\pounds \{ f \} (s) = F(s) = \int _{0} ^ {\infty} e^{-st} f(t) dt\]

Uses

The Laplace Transform is a technique used to solve differential equation when some of the coefficients are not continuous functions.

We first take the Laplace Transform of the equation, then solve the resulting algebra equation for $Y(s)$, and then take the inverse Laplace Transform of $Y(s)$ to get $y$.


Example

Solve the differential equation

\[y''+y= H(t-5)\]

, where $H(t)$ is the Heaviside function, defined as

\[H(x)= \begin{cases} x^2 &\text{if } x \ge 0 \\ x &\text{if } x < 0 \end{cases}\]

Solution:

We take the Laplace transe

See Also

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