Difference between revisions of "2016 AMC 8 Problems/Problem 12"
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+ | ==Solution 2== | ||
+ | Without loss of generality, we can assume that there are 12 girls and 12 boys on the trip, because 12 is the LCM(3, 4). This means 9 girls and 8 boys went on the trip, resulting in 17 students in total. Out of this 9, were girls, so the fraction of girls who went on the trip is <math>\frac{\frac{3}{4}}, which is </math>\boxed{\textbf{(B)} \frac{9}{17}}$. | ||
==Video Solution (CREATIVE THINKING!!!)== | ==Video Solution (CREATIVE THINKING!!!)== |
Revision as of 01:12, 6 January 2025
Contents
Problem
Jefferson Middle School has the same number of boys and girls. of the girls and
of the boys went on a field trip. What fraction of the students on the field trip were girls?
Solution 1
Let there be boys and
girls in the school. We see
, which means
kids went on the trip and
kids are girls. So, the answer is
, which is
.
~CHECKMATE2021
Solution 2
Without loss of generality, we can assume that there are 12 girls and 12 boys on the trip, because 12 is the LCM(3, 4). This means 9 girls and 8 boys went on the trip, resulting in 17 students in total. Out of this 9, were girls, so the fraction of girls who went on the trip is \boxed{\textbf{(B)} \frac{9}{17}}$.
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.