Difference between revisions of "2008 AMC 12A Problems/Problem 18"
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==Problem== | ==Problem== | ||
− | + | Triangle <math>ABC</math>, with sides of length <math>5</math>, <math>6</math>, and <math>7</math>, has one [[vertex]] on the positive <math>x</math>-axis, one on the positive <math>y</math>-axis, and one on the positive <math>z</math>-axis. Let <math>O</math> be the [[origin]]. What is the volume of [[tetrahedron]] <math>OABC</math>? | |
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<math>\textbf{(A)}\ \sqrt{85} \qquad \textbf{(B)}\ \sqrt{90} \qquad \textbf{(C)}\ \sqrt{95} \qquad \textbf{(D)}\ 10 \qquad \textbf{(E)}\ \sqrt{105}</math> | <math>\textbf{(A)}\ \sqrt{85} \qquad \textbf{(B)}\ \sqrt{90} \qquad \textbf{(C)}\ \sqrt{95} \qquad \textbf{(D)}\ 10 \qquad \textbf{(E)}\ \sqrt{105}</math> | ||
==Solution== | ==Solution== | ||
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{{image}} | {{image}} | ||
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which is answer choice C. <math>\blacksquare</math> | which is answer choice C. <math>\blacksquare</math> | ||
− | + | == See also == | |
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{{AMC12 box|year=2008|num-b=17|num-a=19|ab=A}} | {{AMC12 box|year=2008|num-b=17|num-a=19|ab=A}} | ||
[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] |
Revision as of 16:59, 20 February 2008
Problem
Triangle , with sides of length , , and , has one vertex on the positive -axis, one on the positive -axis, and one on the positive -axis. Let be the origin. What is the volume of tetrahedron ?
Solution
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
Without loss of generality, let be on the axis, be on the axis, and be on the axis, and let have respective lenghts of 5, 6, and 7. Let denote the lengths of segments respectively. Then by the Pythagorean Theorem, so ; similarly, and . Since , , and are mutually perpendicular, the tetrahedron's volume is which is answer choice C.
See also
2008 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 17 |
Followed by Problem 19 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |