Difference between revisions of "2024 AMC 10B Problems/Problem 20"
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==Problem== | ==Problem== | ||
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| + | Three different pairs of shoes are placed in a row so that no left shoe is next to a | ||
| + | right shoe from a different pair. In how many ways can these six shoes be lined up? | ||
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| + | <math>\textbf{(A) } 60 \qquad\textbf{(B) } 72 \qquad\textbf{(C) } 90 \qquad\textbf{(D) } 108 \qquad\textbf{(E) } 120</math> | ||
==Solution 1== | ==Solution 1== | ||
Revision as of 03:22, 14 November 2024
Problem
Three different pairs of shoes are placed in a row so that no left shoe is next to a right shoe from a different pair. In how many ways can these six shoes be lined up?
Solution 1
See also
| 2024 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 19 |
Followed by Problem 21 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
