Difference between revisions of "2024 AMC 12B Problems/Problem 15"
(Created page with "==Solution (Shoelace Theorem)== We rewrite: <math>A(0,1)</math> <math>B(\log _{2} 3, 2)</math> <math>C(\log _{2} 7, 3)</math> From here we setup Shoelace Theorem and obtain: <...") |
(→Solution (Shoelace Theorem)) |
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| Line 3: | Line 3: | ||
<math>A(0,1)</math> | <math>A(0,1)</math> | ||
<math>B(\log _{2} 3, 2)</math> | <math>B(\log _{2} 3, 2)</math> | ||
| − | <math>C(\log _{2} 7, 3)</math> | + | <math>C(\log _{2} 7, 3)</math>. |
| + | |||
From here we setup Shoelace Theorem and obtain: | From here we setup Shoelace Theorem and obtain: | ||
<math>\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)</math> | <math>\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)</math> | ||
Revision as of 00:59, 14 November 2024
Solution (Shoelace Theorem)
We rewrite:
.
From here we setup Shoelace Theorem and obtain:
Following log properties and simplifying gives (B).
~PeterDoesPhysics
