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Difference between revisions of "Four fair coins are to be flipped. What is the probability that all four will be heads or all four will be tails? Express your answer as a common fraction."

(Created page with "A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits (<math>\spadesuit</math>, <math>\heartsuit</math>, <math>\diamondsuit...")
 
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A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits (<math>\spadesuit</math>, <math>\heartsuit</math>, <math>\diamondsuit</math>, and <math>\clubsuit</math>), such that there is exactly one card for any given rank and suit. Two of the suits (<math>\spadesuit</math> and <math>\clubsuit</math>) are black and the other two suits (<math>\heartsuit</math> and <math>\diamondsuit</math>) are red. The deck is randomly arranged. What is the probability that the top card is a 5?
 
A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits (<math>\spadesuit</math>, <math>\heartsuit</math>, <math>\diamondsuit</math>, and <math>\clubsuit</math>), such that there is exactly one card for any given rank and suit. Two of the suits (<math>\spadesuit</math> and <math>\clubsuit</math>) are black and the other two suits (<math>\heartsuit</math> and <math>\diamondsuit</math>) are red. The deck is randomly arranged. What is the probability that the top card is a 5?
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Latest revision as of 15:45, 30 October 2024

A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits ($\spadesuit$, $\heartsuit$, $\diamondsuit$, and $\clubsuit$), such that there is exactly one card for any given rank and suit. Two of the suits ($\spadesuit$ and $\clubsuit$) are black and the other two suits ($\heartsuit$ and $\diamondsuit$) are red. The deck is randomly arranged. What is the probability that the top card is a 5?

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