Difference between revisions of "2006 AMC 8 Problems/Problem 8"
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Thus, the percentage of males surveyed that listen to the station is <math> 100 \cdot \frac{78}{104} \%= \boxed{\textbf{(E)}\ 75 \%} </math>. | Thus, the percentage of males surveyed that listen to the station is <math> 100 \cdot \frac{78}{104} \%= \boxed{\textbf{(E)}\ 75 \%} </math>. | ||
| + | ==Video Solution by WhyMath== | ||
| + | https://youtu.be/QYuzANcB_Ec | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|num-b=7|num-a=9}} | {{AMC8 box|year=2006|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 13:22, 29 October 2024
Problem
The table shows some of the results of a survey by radiostation KACL. What percentage of the males surveyed listen to the station?
Solution
Filling out the chart, it becomes
Thus, the percentage of males surveyed that listen to the station is 
.
Video Solution by WhyMath
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
