Difference between revisions of "2024 AMC 10A Problems"

Revision as of 22:27, 9 September 2024

2024 AMC 10A (Answer Key) Printable versions: Wiki • AoPS Resources • PDF
Instructions This is a 25-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct. You will receive 6 points for each correct answer, 2.5 points for each problem left unanswered if the year is before 2006, 1.5 points for each problem left unanswered if the year is after 2006, and 0 points for each incorrect answer. No aids are permitted other than scratch paper, graph paper, ruler, compass, protractor and erasers (and calculators that are accepted for use on the SAT if before 2006. No problems on the test will require the use of a calculator). Figures are not necessarily drawn to scale. You will have 75 minutes working time to complete the test.
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Problem 1

A bug crawls along a number line, starting at $-2$ . It crawls to $-6$ , then turns around and crawls to $5$ . How many units does the bug crawl altogether?

$\textbf{(A)}\ 9\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 13\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 15$

Problem 2

What is the value of $\dfrac{11!-10!}{9!}$ ?

$\textbf{(A)}\ 99\qquad\textbf{(B)}\ 100\qquad\textbf{(C)}\ 110\qquad\textbf{(D)}\ 121\qquad\textbf{(E)}\ 132$

Problem 3

When counting from $3$ to $201$ , $53$ is the $51^{st}$ number counted. When counting backwards from $201$ to $3$ , $53$ is the $n^{th}$ number counted. What is $n$ ?

$\textbf{(A)}\ 146 \qquad \textbf{(B)}\ 147 \qquad \textbf{(C)}\ 148 \qquad \textbf{(D)}\ 149 \qquad \textbf{(E)}\ 150$

Problem 4

What is $\frac{2+4+6}{1+3+5} - \frac{1+3+5}{2+4+6}?$

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ \frac{5}{36} \qquad \textbf{(C)}\ \frac{7}{12} \qquad \textbf{(D)}\ \frac{147}{60} \qquad \textbf{(E)}\ \frac{43}{3}$

Problem 5

At the theater children get in for half price. The price for $5$ adult tickets and $4$ child tickets is $$ (Error compiling LaTeX. Unknown error_msg)24.50 $. How much would$ 8 $adult tickets and$ 6 $child tickets cost?$ \textbf{(A) } $35\qquad \textbf{(B) }$ 38.50\qquad \textbf{(C) } $40\qquad \textbf{(D) }$ 42\qquad \textbf{(E) } $42.50$

@@ Line 28: / Line 28: @@
 ==Problem 5==
+At the theater children get in for half price. The price for <math>5</math> adult tickets and <math>4</math> child tickets is <math></math>24.50<math>. How much would </math>8<math> adult tickets and </math>6<math> child tickets cost?
+</math>\textbf{(A) }<math>35\qquad \textbf{(B) }</math>38.50\qquad \textbf{(C) }<math>40\qquad \textbf{(D) }</math>42\qquad \textbf{(E) }<math>42.50</math>
 ==Problem 6==

2024 AMC 10A (Problems • Answer Key • Resources)
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Difference between revisions of "2024 AMC 10A Problems"

Revision as of 22:27, 9 September 2024

Contents

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

See also