Difference between revisions of "1951 AHSME Problems/Problem 2"

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Revision as of 19:52, 10 January 2008

Problem

The percent that $M$ is greater than $N$, is:

$\mathrm{(A) \ } \frac {100(M - N)}{M} \qquad \mathrm{(B) \ } \frac {100(M - N)}{N} \qquad \mathrm{(C) \ } \frac {M - N}{N} \qquad \mathrm{(D) \ } \frac {M - N}{M} \qquad \mathrm{(E) \ } \frac {100(M + N)}{N}$

Solution

By definition of a percent, the answer is $\mathrm{(B)}$.

See also

1951 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AHSME Problems and Solutions