Difference between revisions of "1959 AHSME Problems/Problem 29"
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To calculate the student's score in terms of <math>n</math>, you can write the following equation: | To calculate the student's score in terms of <math>n</math>, you can write the following equation: | ||
− | + | \frac{\frac{n-20}{3} + 15}{n} = \frac{1}{2}<math>. Simplify to get </math>n=55$, so there is one solution. |
Revision as of 13:15, 16 July 2024
Problem 29
On a examination of questions a student answers correctly of the first . Of the remaining questions he answers one third correctly. All the questions have the same credit. If the student's mark is 50%, how many different values of can there be?
Solution
To calculate the student's score in terms of , you can write the following equation:
\frac{\frac{n-20}{3} + 15}{n} = \frac{1}{2}n=55$, so there is one solution.