Difference between revisions of "2007 AMC 12A Problems/Problem 21"

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To disprove the others, note that:
 
To disprove the others, note that:
*<math>\mathrm{B}</math>: then <math>b = \frac {-b}a</math>, which forces <math>a = -1</math> (not an [[identity]]).
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*<math>\mathrm{B}</math>: then <math>b = \frac {-b}a</math>, which is not necessarily true.
*<math>\mathrm{C}</math>: the [[y-intercept]] is <math>c</math>, so <math>c = \frac ca</math> which forces <math>a = 1</math>.
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*<math>\mathrm{C}</math>: the [[y-intercept]] is <math>c</math>, so <math>c = \frac ca</math>, not necessarily true.
 
*<math>\mathrm{D}</math>: an [[x-intercept]] of the graph is a root of the polynomial, but this excludes the other root.
 
*<math>\mathrm{D}</math>: an [[x-intercept]] of the graph is a root of the polynomial, but this excludes the other root.
 
*<math>\mathrm{E}</math>: the mean of the x-intercepts will be the sum of the roots of the quadratic divided by 2.
 
*<math>\mathrm{E}</math>: the mean of the x-intercepts will be the sum of the roots of the quadratic divided by 2.

Revision as of 17:16, 2 January 2008

Problem

The sum of the zeros, the product of the zeros, and the sum of the coefficients of the function $\displaystyle f(x)=ax^{2}+bx+c$ are equal. Their common value must also be which of the following?

$\textrm{(A)}\ \textrm{the\ coefficient\ of\ }x^{2}~~~ \textrm{(B)}\ \textrm{the\ coefficient\ of\ }x$ $\textrm{(C)}\ \textrm{the\ y-intercept\ of\ the\ graph\ of\ }y=f(x)$ $\textrm{(D)}\ \textrm{one\ of\ the\ x-intercepts\ of\ the\ graph\ of\ }y=f(x)$ $\textrm{(E)}\ \textrm{the\ mean\ of\ the\ x-intercepts\ of\ the\ graph\ of\ }y=f(x)$

Solution

By Vieta's formulas, the sum of the roots of a quadratic equation is $\frac {-b}a$, the product of the zeros is $\frac ca$, and the sum of the coefficients is $a + b + c$. Setting equal the first two tells us that $\frac {-b}{a} = \frac ca \Rightarrow b = -c$. Thus, $a + b + c = a + b - b = a$, so the common value is also equal to the coefficient of $x^2 \Longrightarrow \textrm{A}$.

To disprove the others, note that:

  • $\mathrm{B}$: then $b = \frac {-b}a$, which is not necessarily true.
  • $\mathrm{C}$: the y-intercept is $c$, so $c = \frac ca$, not necessarily true.
  • $\mathrm{D}$: an x-intercept of the graph is a root of the polynomial, but this excludes the other root.
  • $\mathrm{E}$: the mean of the x-intercepts will be the sum of the roots of the quadratic divided by 2.

See also

2007 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 20
Followed by
Problem 22
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions